Web3 okt. 2024 · If sin θ +cos θ =p and sec θ + cosec θ =q, then prove that q(p^2 - 1)=2p. asked Aug 28, 2024 in Trigonometry by Shyam01 (50.9k points) trigonometry; class-10; 0 votes. 1 answer. यदि sin θ + cos θ = p और sec θ + cosec θ = q हो, तो सिद्ध कीजिए: q(p^2 – 1) = 2p. Web24 mrt. 2024 · Hint: In order to solve the problem start with the terms in the G.P. Use the property of G.P. in order to form the equation of the required form by the use of trigonometric identities such as
Simplify the trigonometric expression (sec(x)-cos(x))/(tan(x)
Web24 jan. 2016 · If A = sin 20 θ + cos 48 θ, then for all values θ a) A ≥ 1 b) 0 < A ≤ 1 c) 1 < A < 3 d) None of these 0 ≤ sin 20 θ ≤ 1 0 ≤ cos 48 θ ≤ 1 So I think it is d.) , but I am confused. I look for a short and simple way. I have studied maths upto 12 th grade. trigonometry Share Cite Follow edited Jan 24, 2016 at 5:13 Em. 15.8k 7 26 39 WebIf `sin theta+ cos theta = p` and `sec theta + cosec theta = q`; show that `q (p^2-1) = 2p`. 2,031 views. Dec 20, 2024. 50 Dislike Share. Doubtnut. 2.29M subscribers. To ask … tax prep sites rated
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Web8 nov. 2024 · cosec θ - sin θ = p 3 and sec θ - cos θ = q 3 Concept used : 1 - sin 2 θ = cos 2 θ 1 - cos 2 θ = sin 2 θ Calculations : cosec θ - sin θ = 1/ (sin θ) - sin θ ⇒ (1 - sin 2 θ)/sin θ ⇒ (cos 2 θ)/ (sin θ) So, (cos 2 θ)/ (sin θ) = p 3 .... (1) Now sec θ - cos θ = (1/cos θ) - cos θ ⇒ (1 - cos 2 θ)/cos θ ⇒ (sin 2 θ)/ (cos θ) So, Web4 jun. 2024 · ⇒ sec θ – tan θ = P ---- (1) As we know, sec 2 θ – tan 2 θ = 1 ⇒ (sec θ – tan θ) (sec θ + tan θ) = 1 ⇒ sec θ + tan θ = 1/P ---- (2) Adding equation (1) and equation (2) ⇒ 2sec θ = P + 1/P ⇒ sec θ = (P 2 + 1)/2P ⇒ cos θ = 2P/ (P 2 + 1) We know, sin 2 θ = 1 – cos 2 θ ⇒ sin 2 θ = 1 – [ (2P) 2 / (P 2 + 1) 2] WebIf pcosθ= qsinθ, then sec2θp + cosec2θq is A p B 0 C qp D qp Hard Solution Verified by Toppr Correct option is A) If pcosθ= qsinθ, So pcos2θ+qsin2θ= 1+ p 2q 2p(1− p 2q 2)+q. … tax prep software 2018